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","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":43,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-09-13T13:18:57.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"ls1955"},"exercise":{"title":"Λειτουργίες λίστας","icon_url":"https://assets.exercism.org/exercises/list-ops.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/el/tracks/crystal/exercises/list-ops/solutions/ls1955","private_iterations_url":"https://exercism.org/el/tracks/crystal/exercises/list-ops/iterations"}},{"uuid":"253ff9f0dc4e467bb87bbdb0c5056960","snippet":"module ListOps(T) def self.append(list1 : Array(T), list2 : Array(T)) : Array(T) result = list1.clone list2.each {|x| result << x} result end def self.concat(lists : Array(Array(T))) result = [] of T lists.each {|list| result = append(result, list)} ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":56,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2025-04-09T15:18:34.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"alterpatzer"},"exercise":{"title":"Λειτουργίες λίστας","icon_url":"https://assets.exercism.org/exercises/list-ops.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/el/tracks/crystal/exercises/list-ops/solutions/alterpatzer","private_iterations_url":"https://exercism.org/el/tracks/crystal/exercises/list-ops/iterations"}},{"uuid":"aedb55f0e7794b7abc77862e26f5d8f9","snippet":"module ListOps(T) # Write your code for the 'List Ops' exercise in this file. def self.append(list1 : Array(T), list2 : Array(T)) : Array(T) result = list1.dup list2.each do |item| result << item end result end def self.concat(lists : Array(Array(T))) ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":51,"iteration_status":"non_actionable_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-09-26T13:59:05.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"menketechnologies"},"exercise":{"title":"Λειτουργίες λίστας","icon_url":"https://assets.exercism.org/exercises/list-ops.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/el/tracks/crystal/exercises/list-ops/solutions/menketechnologies","private_iterations_url":"https://exercism.org/el/tracks/crystal/exercises/list-ops/iterations"}}],"meta":{"current_page":1,"total_count":17,"total_pages":1,"unscoped_total":17}}}}}

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