datetime addition

Δίσεκτο έτος
Δίσεκτο έτος στη διαδρομή Python 
from datetime import datetime, timedelta


def leap_year(year):
    return (datetime(year, 2, 28)
            + timedelta(days=1)).day == 29
Note

This approach may be considered a "cheat" for this exercise, which is intended to practice Boolean operators and boolean logic. It also adds overhead in both performance and memory, as it imports methods from the datetime module and requires the instantiation of both a datetime object and a timedelta object.

For more information, see the performance article for this exercise.

By adding a day to February 28th for a given year, you can see if the new day falls on the 29th of February or the 1st of March. If it is February 29th, then the function returns True for the year being a leap year. The exact steps are as follows:

  • A new datetime object is created for February 28th of the year.
  • A timedelta of one day is added to that datetime.
  • The function returns if the day property of the resulting datetime object is the 29th.
Translation missing: el.number.nth.ordinalized Sep 2026 · Σου φάνηκε χρήσιμη;

Άλλες προσεγγίσεις για την άσκηση Δίσεκτο έτος στη διαδρομή Python

Άλλοι τρόποι με τους οποίους η κοινότητά μας έλυσε αυτή την άσκηση
def leap_year(year):
    return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)
Boolean chain

Use a chain of boolean expressions. 

def leap_year(year):
    return not year % 400 if not year % 100 else not year % 4
Ternary operator

Use a ternary operator of boolean expressions. 

from calendar import isleap

def leap_year(year):
    return isleap(year)
calendar.isleap() function

Use the calendar module.