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(2*sum*a) b = rhs/lhs c = sum - a - b [a,b,c] end ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":15,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-05-16T10:57:05.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"namtax"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/namtax","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"1a88faff84ab444b8a00c103972212ff","snippet":"class PythagoreanTriplet def self.triplets_with_sum(sum) a_limit = (sum / 3) (1..a_limit).map do |a| b = (sum**2 - 2 * sum * a) / (2 * sum - 2 * a) c = sum - (a + b) [a,b,c] end .select{|a,b,c| a < b && b < c && a**2 + b**2 == c**2} end ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":11,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-03-09T17:04:55.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"usborn116"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/usborn116","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"915cfc538bcc4a809e0a4eb6359faf34","snippet":"module PythagoreanTriplet def self.triplets_with_sum(number) a_limit = (number / 3) result = [] (1..a_limit).each do |a| b = (number**2 - 2 * number * a) / (2 * number - 2 * a) c = number - (a + b) result << [a, b, c].sort ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":12,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-09-11T14:11:37.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"rodrigosantiag"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/rodrigosantiag","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"785a13c3f7034f2abe5d152e9e7f7670","snippet":"class PythagoreanTriplet def self.triplets_with_sum(sum) (1..sum/3).each_with_object([]) do |a, result| b = (sum**2 - 2 * sum * a) / (2 * sum - 2 * a) c = sum - (a + b) result << [a, b, c] if a > 0 && a < b && b < c && a**2 + b**2 == c**2 end.uniq end end","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":9,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-08-28T06:33:57.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"diegopolido"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/diegopolido","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"afe07c6b073e4f5fad912edf786fcca6","snippet":"module PythagoreanTriplet def self.triplets_with_sum(n) (1..n/3).each_with_object([]) do |a, result| b = (n - 2 * a) * n / (2 * (n - a)) c = n - a - b result << [a,b,c] if (a + b + c == n) && (c > b && b > a) && (a**2 + b**2 == c**2) end end end","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":9,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-09-18T22:36:40.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"MatheusOB21"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/MatheusOB21","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"1fa116de114c468d862004f10ca9164e","snippet":"class Triplet attr_reader :sides, :a, :b, :c def initialize(*sides) @sides = *sides.sort # ensures a < b < c @a = sides[0] @b = sides[1] @c = sides[2] ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":55,"iteration_status":"tests_failed","published_iteration_head_tests_status":"exceptioned","published_at":"2019-04-14T09:59:06.000Z","is_out_of_date":true,"language":"ruby","author":{"handle":"btihen"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/btihen","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"73f1b7b154a34faca66c968d5bcdc4be","snippet":"class Triplet attr_reader :a, :b, :c def initialize(a,b,c) @a = a @b = b @c = c end ","num_views":0,"num_stars":2,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":30,"iteration_status":"tests_failed","published_iteration_head_tests_status":"exceptioned","published_at":"2019-11-18T07:27:51.000Z","is_out_of_date":true,"language":"ruby","author":{"handle":"StephenVNelson"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/StephenVNelson","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"be654a192e7d4cbaba7e467dbd888a78","snippet":"class Triplet attr_reader :sides def initialize(*sides) @sides = sides end def sum sides.reduce(:+) ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":23,"iteration_status":"tests_failed","published_iteration_head_tests_status":"exceptioned","published_at":"2019-07-11T18:36:31.000Z","is_out_of_date":true,"language":"ruby","author":{"handle":"cashmann"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/cashmann","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"e8c6e1e4e24c4cb08479bcb6132417fd","snippet":"class PythagoreanTriplet def self.triplets_with_sum(num) a_start = num / 3 (1..a_start).each_with_object([]) do |a, acc| b_start = (num - a) / 2 b_start.downto(a + 1) do |b| c = num - (a + b) break if a**2 + b**2 < c**2 acc << [a, b, c] if a**2 + b**2 == c**2 ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":4,"num_loc":13,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-04-11T13:15:23.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"jkyo"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/jkyo","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"3f8c6f39998f48c6b362c0cb3ff9f5f4","snippet":"module PythagoreanTriplet def self.triplets_with_sum(n) (1...n).each_with_object([]) do |a, res| b = (n * (2 * a - n)) / (2 * (a - n)).to_f c = n - a - b res << [a, b.to_i, c.to_i] if b % 1 == 0 && a < b end end end","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":9,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-07-03T00:12:37.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"JakubSarnik"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/JakubSarnik","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"6fbad259b1434edfa80fb622092ffb72","snippet":"class PythagoreanTriplet # @param [String] n def self.triplets_with_sum(sum) (1..(sum / 3).floor).each_with_object([]) do |a, result| (a + 1..(sum / 2).floor).each do |b| c = sum - a - b result.push([a, b, c]) if a**2 + b**2 == c**2 end end end ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":10,"iteration_status":"testing","published_iteration_head_tests_status":"exceptioned","published_at":"2024-07-22T00:09:46.000Z","is_out_of_date":true,"language":"ruby","author":{"handle":"fauzanalghifary"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/fauzanalghifary","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"28cdf689d8d84528b315cd41fa56ff6a","snippet":"class PythagoreanTriplet def self.triplets_with_sum(number) #(1..(number-3)).to_a.combination(3).select{|b| ( b[0] + b[1] + b[2] == number && b[0]**2 + b[1]**2) == b[2]**2} a = 1 half_number = number.to_f / 2.0 comb = [] while (a < number/3) do b = a + 1 c = number - a - b while ( b < c ) do ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":20,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-06-18T02:11:14.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"EnriqueDorantes"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/EnriqueDorantes","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"a61dce2629384c3ba7c8aad19c036f19","snippet":"class PythagoreanTriplet def self.triplets_with_sum(sum) triples = [] (1..sum-1).each do |a| b = (sum * sum - 2 * sum * a) / (2 * sum - 2 * a) c = sum - a - b if pythagorian?(a, b, c) triples.push([a, b, c]) ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":16,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-10-03T15:56:23.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"stefanoa0"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/stefanoa0","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}},{"uuid":"6363492956ee4e9291e6d94254aa17ba","snippet":"class PythagoreanTriplet def self.triplets_with_sum(sum) triplets = [] (1..sum / 3).each do |side_a| side_b = (sum**2 - 2 * sum * side_a) / (2 * sum - 2 * side_a) side_c = sum - side_a - side_b if side_a**2 + side_b**2 == side_c**2 ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":13,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-06-12T01:38:40.000Z","is_out_of_date":false,"language":"ruby","author":{"handle":"juanpabloow"},"exercise":{"title":"Πυθαγόρεια τριάδα","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Ruby","icon_url":"https://assets.exercism.org/tracks/ruby.svg","highlightjs_language":"ruby"},"links":{"public_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/solutions/juanpabloow","private_iterations_url":"https://exercism.org/el/tracks/ruby/exercises/pythagorean-triplet/iterations"}}],"meta":{"current_page":1,"total_count":146,"total_pages":7,"unscoped_total":146}}}}}

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