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square_of_sum(n: u32) -> u32 { (1..=n).sum::().pow(2) } pub fn sum_of_squares(n: u32) -> u32 { (1..=n).map(|x| x*x).sum::() } pub fn difference(n: u32) -> u32 { square_of_sum(n) - sum_of_squares(n) ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":42,"num_iterations":1,"num_loc":9,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2018-10-19T20:28:04.000Z","is_out_of_date":false,"language":"rust","author":{"handle":"yever"},"exercise":{"title":"Διαφορά Τετραγώνων","icon_url":"https://assets.exercism.org/exercises/difference-of-squares.svg"},"track":{"title":"Rust","icon_url":"https://assets.exercism.org/tracks/rust.svg","highlightjs_language":"rust"},"links":{"public_url":"https://exercism.org/el/tracks/rust/exercises/difference-of-squares/solutions/yever","private_iterations_url":"https://exercism.org/el/tracks/rust/exercises/difference-of-squares/iterations"}},{"uuid":"fcc33706753a412bb42e9727ffe51132","snippet":"pub fn square_of_sum(n: usize) -> usize { (1..n + 1).sum::().pow(2) } pub fn sum_of_squares(n: usize) -> usize { (1..n + 1).map(|i| i.pow(2)).sum() } pub fn difference(n: usize) -> usize { square_of_sum(n) - sum_of_squares(n) 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