{"request":{"endpoint":"https://exercism.org/api/v2/tracks/crystal/exercises/pythagorean-triplet/community_solutions","query":{},"options":{"initial_data":{"results":[{"uuid":"e8af22588bc74b2c9b410328cb2bcd13","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) triplets = [] of Array(Int32) # Loop over possible values for a and b using the .each iterator 1.upto(sum - 1) do |a| (a + 1).upto(sum - a - 1) do |b| c = sum - a - b # Check if a, b, c form a Pythagorean triplet ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":2,"num_iterations":1,"num_loc":14,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-02-09T14:34:37.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"david82"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/david82","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"b9b9e68f3ac64577b078796c6d7edee1","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) n2by2 = (sum * sum)//2 result = Array(Array(Int32)).new (1..sum//3).each do |a| ((a + 1)..((sum - a)//2)).each do |b| if sum*(a + b) - a*b == n2by2 result << [a, b, sum - a - b] end end ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":14,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-02-21T16:58:20.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"radha-8784"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/radha-8784","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"74ed740b2634405585a31333a0ccecd5","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) triplets = [] of Array(Int32) mid = sum // 2 a = 1 while a < mid b = a + 1 c = sum - 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a - b) > b erg.push([a,b,c]) if a*a + b*b == c*c end ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":26,"iteration_status":"actionable_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2026-01-07T17:37:38.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"boris-mb"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/boris-mb","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"1c5db7c5d12a4286a192ea6c4fa35232","snippet":"module PythagoreanTriplet # Find all Pythagorean triplets where a + b + c = sum def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) triplets = [] of Array(Int32) # Maximum value for a (since a < b < c and a + b + c = sum) a_max = (sum // 3) # Iterate through possible values of a (3..a_max).each do |a| ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":17,"iteration_status":"non_actionable_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2025-06-23T21:03:31.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"VickMahase"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/VickMahase","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"b67824ff00264e6e851559327627bbcc","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) triplets = Array(Array(Int32)).new (1..sum // 3).each do |a| ((a + 1)..((sum - a) // 2)).each do |b| c = sum - a - b triplets << [a, b, c] if c**2 == a**2 + b**2 end end triplets ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":1,"num_loc":12,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2026-06-03T13:12:17.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"IlOl95"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/IlOl95","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"4ec8b3b1f467455491f6234faec054a7","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) # Write your code for the 'Pythagorean Triplet' exercise in this file. triplets = [] of Array(Int32) (1...(sum/3)).each do |a| ((a + 1)...((sum - a) / 2)).each do |b| c = sum - a - b triplets << [a, b, c] if (c * c) == ((a * a) + (b * b)) ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":12,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-06-23T00:34:26.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"igbanam"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/igbanam","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"63a95aa8ed03491d9a04e1325831faa8","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) triplets = [] of Array(Int32) 1.upto(sum - 5) do |a| (a + 1).upto(sum - a - 1) do |b| c = sum - a - b if b > c break end ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":17,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-05-23T21:44:04.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"avrame"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/avrame","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"5b1e6509a05b4f90b75e7aeb961d7ebc","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) result = [] of Array(Int32) (1..sum / 3).each do |a| # Given below two equations: # a**2 + b**2 = c**2 # a + b + c = sum, which means c = sum - a - b # # Substitude second equation back into first equation ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":3,"num_loc":13,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2024-09-01T06:02:45.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"ls1955"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/ls1955","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"bec88738f8914b62abdae88a2f466666","snippet":"module PythagoreanTriplet alias Solution = Array(Int32) def self.triplets_with_sum(sum : Int32) : Array(Solution) solutions = Array(Solution).new # a < b < c, so a <= sum //3 # b has to be at least a+1 and also large enough such that a+b>=sum//2 (triangle inequality) # b has to be smaller than sum - a - (a+1) (3..sum//3).each do |a| (Math.max(a + 1, sum//2 - a)...sum - 2*a).each do |b| ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":3,"num_loc":14,"iteration_status":"no_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2026-09-09T13:35:59.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"swsch"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/swsch","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}},{"uuid":"776c8f1687a5421e8646457cd4aa46a7","snippet":"module PythagoreanTriplet def self.triplets_with_sum(sum : Int32) : Array(Array(Int32)) triplets = [] of Array(Int32) (1...(sum / 3)).each do |a| ((a + 1)...((sum - 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a²) / (2(b + c)) b_plus_c = sum - a b = (b_plus_c ** 2 - a ** 2) // ( 2 * b_plus_c) c = (Math.sqrt ( a ** 2 + b ** 2 )).to_i32 if a < b && a + b + c == sum [a,b,c] else ","num_views":0,"num_stars":0,"num_comments":0,"representation_num_published_solutions":1,"num_iterations":2,"num_loc":15,"iteration_status":"actionable_automated_feedback","published_iteration_head_tests_status":"passed","published_at":"2023-03-01T23:14:38.000Z","is_out_of_date":false,"language":"crystal","author":{"handle":"rebelwarrior"},"exercise":{"title":"पाइथागोरस त्रिक","icon_url":"https://assets.exercism.org/exercises/pythagorean-triplet.svg"},"track":{"title":"Crystal","icon_url":"https://assets.exercism.org/tracks/crystal.svg","highlightjs_language":"crystal"},"links":{"public_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/solutions/rebelwarrior","private_iterations_url":"https://exercism.org/hi/tracks/crystal/exercises/pythagorean-triplet/iterations"}}],"meta":{"current_page":1,"total_count":13,"total_pages":1,"unscoped_total":13}}}}}

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