ordered hashtable

Raindrops
Raindrops in PowerShell 
function Raindrops() {
    [CmdletBinding()]
    Param(
        [int]$Number
    )
    $table = [ordered]@{
        3 = "Pling"
        5 = "Plang"
        7 = "Plong"
    }
    $sounds = foreach ($key in $table.Keys) {
        if ($Number % $key -eq 0) {
            $table.$key
        }
    }
    $sounds.Count -eq 0 ? "$Number" : -join $sounds
}

This approach loops through an ordered hashtable's keys. If the input number is divisible by a key, retrieve the string associated with the key from the hashtable. The loop can be assigned to a variable to represent the final collection of sounds.

$sounds = foreach ($key in $table.Keys) {
        if ($Number % $key -eq 0) {
            $table.$key
        }
    }

If the collection is empty at the end, return the original number as string.

$sounds.Count -eq 0 ? "$Number" : -join $sounds

foreach loop.

Hashtable data structure.

6th Nov 2024 · Found it useful?

Other Approaches to Raindrops in PowerShell

Other ways our community solved this exercise
$sounds = ""
if ($Number % 3 -eq 0) {$sounds += "Pling"}
if ($Number % 5 -eq 0) {$sounds += "Plang"}
if ($Number % 7 -eq 0) {$sounds += "Plong"}
$sounds.Length -eq 0 ? "$Number" : $sounds
if statements

Multiple if statements. 

$sounds = switch (0) {
        ($number % 3) {"Pling"}
        ($number % 5) {"Plang"}
        ($number % 7) {"Plong"}
        Default {$number}
    }
-join $sounds
switch statement

Utilizing switch statement.