Ternary operator

Leap
Leap in Rust
pub fn is_leap_year(year: u64) -> bool {
    if year % 100 == 0 {
        year % 400 == 0
    } else {
        year % 4 == 0
    }
}

Unlike other languages, Rust does not have a ternary operator such as ? that is used like so

// this is NOT valid Rust code
a > b ? a : b

where a is tested to be greater than b, and , if so, returns a, otherwise it returns b. Note that the line of code returns a or b without using a return keyword.

Because Rust is an expression-based language, a simple if/else works like a ternary expression in other languages.

In this code

if year % 100 == 0 {
    year % 400 == 0
}

year is tested to be evenly divislbe by 100 by using the remainder operator. If so, it returns if year is evenly divisible by 400, as the last expression evaluated in the function.

Note

Note that the line is just year % 400 == 0. This is because the last expression can be returned from a function without using return and a semicolon.

If year is not evenly divisible by 100, then else is the last expression evaluated in the function

else {
    year % 4 == 0
}

and returns if year is evenly divisible by 4.

year year % 100 == 0 year % 400 == 0 year % 4 == 0 is leap year
2020 false not evaluated true true
2019 false not evaluated false false
2000 true true not evaluated true
1900 true false not evaluated false

Although it uses a maximum of only two checks, the ternary operator tests an outlier condition first, making it less efficient than another approach that would first test if the year is evenly divisible by 4, which is more likely than the year being evenly divisible by 100.

8th May 2024 · Found it useful?