LocalDate plusDays

Leap
Leap in Scala 
import java.time.{LocalDate, Month}

object Leap {
  def leapYear(year: Int): Boolean =
    LocalDate.of(year, Month.FEBRUARY, 28).plusDays(1).getDayOfMonth() == 29
}

This approach may be considered a "cheat" for this exercise. By adding a day to February 28th for the year, you can see if the new day is the 29th or the 1st. If it is the 29th, then the year is a leap year. This is done by using the plusDays() and getDayOfMonth() methods of the LocalDate class.

8th May 2024 · Found it useful?

Other Approaches to Leap in Scala

Other ways our community solved this exercise
def leapYear(year: Int): Boolean =
  year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)
Boolean chain

Use a chain of boolean expressions. 

def leapYear(year: Int): Boolean =
  if (year % 100 == 0) year % 400 == 0
  else year % 4 == 0
Ternary expression

Use a ternary expression of boolean conditions. 

def leapYear(year: Int): Boolean =
  (year % 4, year % 100, year % 400) match {
    case (_, _, 0) => true
    case (_, 0, _) => false
    case (0, _, _) => true
    case (_, _, _) => false
  }
match on a tuple

Use a match on a tuple made from boolean expressions. 

import java.time.{Year}

object Leap {
  def leapYear(year: Int): Boolean =
    Year.of(year).isLeap()
}
Built-in method

Use the built-in method.