Train Driver

const [a, b, ...everythingElse] = [0, 1, 1, 2, 3, 5, 8];
a;
// => 0
b;
// => 1
everythingElse;
// => [1, 2, 3, 5, 8]

const [...items, last] = [2, 4, 8, 16]

const { street, ...address } = {
  street: 'Platz der Republik 1',
  postalCode: '11011',
  city: 'Berlin',
};
street;
// => 'Platz der Republik 1'
address;
// => {postalCode: '11011', city: 'Berlin'}

function concat(...strings) {
  return strings.join(' ');
}
concat('one');
// => 'one'
concat('one', 'two', 'three');
// => 'one two three'

const oneToFive = [1, 2, 3, 4, 5];
const oneToTen = [...oneToFive, 6, 7, 8, 9, 10];
oneToTen;
// => [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
const woow = ['A', ...oneToFive, 'B', 'C', 'D', 'E', ...oneToFive, 42];
woow;
// =>  ["A", 1, 2, 3, 4, 5, "B", "C", "D", "E", 1, 2, 3, 4, 5, 42]

let address = {
  postalCode: '11011',
  city: 'Berlin',
};
address = { ...address, country: 'Germany' };
// => {
//   postalCode: '11011',
//   city: 'Berlin',
//   country: 'Germany',
// }

Instructions

Your friend Linus is a train driver who drives cargo trains between cities. Although they are amazing at handling trains, they are not amazing at handling logistics or computers. They would like to enlist your programming help organizing train details and correcting mistakes in route data.

1. Create a list of all wagons

Your friend has been keeping track of each wagon identifier (ID), but they are never sure how many wagons the system is going to have to process at any given time. It would be much easier for the rest of the logistics program to have this data packaged into a unified array.

Implement a function getListOfWagons that accepts an arbitrary number of wagon IDs which are the IDs of each wagon. Each ID will be a positive integer. The function should then return the given IDs as a single array.

getListOfWagons(1, 7, 12, 3, 14, 8, 5);
// => [1, 7, 12, 3, 14, 8, 5]

2. Move the first two elements to the end of the array

At this point, you are starting to get a feel for the data and how it's used in the logistics program. The ID system always assigns the locomotive an ID of 1, with the remainder of the wagons in the train assigned a randomly chosen ID greater than 1.

Your friend had to connect two new wagons to the train and forgot to update the system! Now, the first two wagons in the train array have to be moved to the end, or everything will be out of order.

Linus would be really grateful to you for fixing their mistakes.

Implement a function fixListOfWagons that accepts an array of the id of each wagon. It returns an array where the 2 first elements repositioned to the end of the array so that the locomotive can be in the front.

eachWagonsID = [2, 5, 1, 7, 4, 12, 6, 3, 13];
fixListOfWagons(eachWagonsID);
// => [1, 7, 4,  12, 6, 3, 13, 2, 5]

3. Add missing values

Uh-oh. some wagons seem to have gone missing.

Fortunately, your friend just found another array which appears to contain the missing wagon IDs, and would like you to add them into the main wagon ID array. All they can remember is that the missing values should be placed directly after the designated locomotive.

Given this new information, write a function called correctListOfWagons that takes two arrays which have the IDs of each wagon as the arguments. The wagon IDs of the second array should be added into the first array directly after the locomotive (ID 1).

eachWagonsID = [1, 5, 20, 7, 4, 8];
missingWagons = [3, 17, 6, 15];
correctListOfWagons(eachWagonsID, missingWagons);
// => [1, 3, 17, 6, 15, 5, 20, 7, 4, 8]

4. Extend routing information

Now that all the wagon data is correct, your friend would like you to update the systems routing information. Initial routing information has been constructed as an object, and you friend would like you to update it with the additions provided. Every route requires slightly different information, so your friend would really prefer a generic solution.

Implement a function extendRouteInformation that accepts two objects. The first object contains which cities the train route moves between.

The second object contains other routing details such as train speed or length. The function should return a consolidated object with all routing information.

route = { from: 'Berlin', to: 'Hamburg' };
moreRouteInformation = { length: '100', speed: '50' };
extendRouteInformation(route, moreRouteInformation);
// => {from: "Berlin", to: "Hamburg", length: "100", speed: "50"}

5. Separate arrival time from routing information

Your friend has noticed that they don't need the arrival time in the routing information. Therefore your friend would like you to separate the arrival time from the routing information.

Implement a function separateTimeOfArrival that accepts an object with the routing information. The function should return an array where the first element of the array is the arrival time and the second element is an object with the routing information without arrival time.

routeInformation = {
  from: 'Berlin',
  to: 'Hamburg',
  length: '100',
  timeOfArrival: '10:10',
};
separateTimeOfArrival(routeInformation);
// => ["10:10", {from: "Berlin", to: "Hamburg", length: "100"}]