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def response(hey_bob):
hey_bob = hey_bob.rstrip()
if not hey_bob:
return 'Fine. Be that way!'
is_shout = hey_bob.isupper()
is_question = hey_bob.endswith('?')
if is_shout:
if is_question:
return "Calm down, I know what I'm doing!"
return 'Whoa, chill out!'
if is_question:
return 'Sure.'
return 'Whatever.'
In this approach you have a series of if statements using the calculated variables to evaluate the conditions, some of which are nested.
As soon as a True condition is found, the correct response is returned.
Note that there are no elif or else statements.
If an if statement can return, then an elif or else is not needed.
Execution will either return or will continue to the next statement anyway.
The rstrip method is applied to the input to eliminate any whitespace at the end of the input.
If the input has no characters left, it uses the falsiness of an empty string with the not operator to return the response for saying nothing.
Since it doesn't matter if there is leading whitespace, the rstrip function is used instead of strip.
The isupper method is used to test that there is at least one cased character and that all cased characters are uppercase.
A cased character is one which differs between lowercase and uppercase.
For example, ? and 3 are not cased characters, as they do not change between lowercase and uppercase.
a and z are cased characters, since their lowercase form changes to A and Z when uppercase.
The endswith method is used to determine if the input ends with a question mark.
Instead of testing a shout and a question on the same line, this approach first tests if the input is a shout.
If it is a shout, then the nested if/else statement returns if it is a shouted question or just a shout.
If it is not a shout, then the flow of execution skips down to the non-nested test for if the input is a question.
