Space Age

Space Age

Easy

Instructions

Given an age in seconds, calculate how old someone would be on:

  • Mercury: orbital period 0.2408467 Earth years
  • Venus: orbital period 0.61519726 Earth years
  • Earth: orbital period 1.0 Earth years, 365.25 Earth days, or 31557600 seconds
  • Mars: orbital period 1.8808158 Earth years
  • Jupiter: orbital period 11.862615 Earth years
  • Saturn: orbital period 29.447498 Earth years
  • Uranus: orbital period 84.016846 Earth years
  • Neptune: orbital period 164.79132 Earth years

So if you were told someone were 1,000,000,000 seconds old, you should be able to say that they're 31.69 Earth-years old.

If you're wondering why Pluto didn't make the cut, go watch this YouTube video.

Note: The actual length of one complete orbit of the Earth around the sun is closer to 365.256 days (1 sidereal year). The Gregorian calendar has, on average, 365.2425 days. While not entirely accurate, 365.25 is the value used in this exercise. See Year on Wikipedia for more ways to measure a year.

For the Python track, this exercise asks you to create a SpaceAge class (classes) that includes methods for all the planets of the solar system. Methods should follow the naming convention on_<planet name>.

Each method should return the age ("on" that planet) in years, rounded to two decimal places:

#creating an instance with one billion seconds, and calling .on_earth().
>>> SpaceAge(1000000000).on_earth()

#This is one billion seconds on Earth in years
31.69

For more information on constructing and using classes, see:

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