You plan to build a tree house in the woods near your house so that you can watch the sun rise and set.
You've obtained data from a local survey company that show the height of every tree in each rectangular section of the map. You need to analyze each grid on the map to find good trees for your tree house.
A good tree is both:
Your task is to find the potential trees where you could build your tree house.
The data company provides the data as grids that show the heights of the trees. The rows of the grid represent the east-west direction, and the columns represent the north-south direction.
An acceptable tree will be the largest in its row, while being the smallest in its column.
A grid might not have any good trees at all. Or it might have one, or even several.
Here is a grid that has exactly one candidate tree.
1 2 3 4
|-----------
1 | 9 8 7 8
2 | 5 3 2 4 <--- potential tree house at row 2, column 1, for tree with height 5
3 | 6 6 7 1
So the point at [2, 1]
(row: 2, column: 1) is a great spot for a tree house.
By convention, ordered sequences of values in Rust have their contents numbered ("indexed") starting from 0. This applies regardless of what the rest of the exercise description in this README says, such as references to indices that start at 1, so you will have to subtract 1 to translate those index numbers to Rust index numbers.
This exercise uses a vector of vectors to store the content of matrices. While this exercise is designed to help students understand basic concepts about vectors, such as indexing, and that nested data types are legal, vector of vectors is a suboptimal choice for high-performance matrix algebra and any similar efficient processing of larger amounts of data.
The detailed explanation of this inefficiency is beyond the scope of this exercise and this learning track in general. This aspect is known as cache locality and you can find a good introduction to it by clicking that link if you'd like to learn more about details of a modern computer architecture.
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