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Word Count
Word Count

Word Count

Medium

Instructions

Given a phrase, count the occurrences of each word in that phrase.

For the purposes of this exercise you can expect that a word will always be one of:

  1. A number composed of one or more ASCII digits (ie "0" or "1234") OR
  2. A simple word composed of one or more ASCII letters (ie "a" or "they") OR
  3. A contraction of two simple words joined by a single apostrophe (ie "it's" or "they're")

When counting words you can assume the following rules:

  1. The count is case insensitive (ie "You", "you", and "YOU" are 3 uses of the same word)
  2. The count is unordered; the tests will ignore how words and counts are ordered
  3. Other than the apostrophe in a contraction all forms of punctuation are ignored
  4. The words can be separated by any form of whitespace (ie "\t", "\n", " ")

For example, for the phrase "That's the password: 'PASSWORD 123'!", cried the Special Agent.\nSo I fled. the count would be:

that's: 1
the: 2
password: 2
123: 1
cried: 1
special: 1
agent: 1
so: 1
i: 1
fled: 1

Running and testing your solutions

From the command line

Simply type make chez if you're using ChezScheme or make guile if you're using GNU Guile. Sometimes the name for the scheme binary on your system will differ from the defaults. When this is the case, you'll need to tell make by running make chez chez=your-chez-binary or make guile guile=your-guile-binary.

From a REPL

  • Enter (load "test.scm") at the repl prompt.
  • Develop your solution in word-count.scm reloading as you go.
  • Run (test) to check your solution.

Failed Test Cases

If some of the test cases fail, you should see the failing input and the expected output. The failing input is presented as a list because the tests call your solution by (apply word-count input-list). To learn more about apply see The Scheme Programming Language -- Chapter 5


Source

This is a classic toy problem, but we were reminded of it by seeing it in the Go Tour.
Last updated 17 November 2021
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